--[[
This module is intended for processing of date strings.
Please do not modify this code without applying the changes first at Module:ISOdate/sandbox and testing at Module:ISOdate/sandbox/testcases and Module talk:ISOdate/sandbox/testcases.
Authors and maintainers:
- User:Parent5446 - original version of the function mimicking template:ISOdate
- User:Jarekt - original version of the functions mimicking template:Date and template:ISOyear
]]
local p = {}
-- ======================================= -- === Dependencies ====================== -- ======================================= local D = require('Module:Date2')
--[[ ISOyear
This function returns year part of date string.
Usage:
Parameters
1: The date string
Error Handling:
If the string does not look like it contain the year than the function will not return anything. That is the preferred treatment for the template:Creator which is the main (only?) template calling it.
]] function p.ISOyear( frame ) local input = frame.args[1] if not input then input = frame.args["s"] end input = mw.text.trim( input )
-- if empty string then return it if input == "" then return input end
-- if number then return it if tonumber( input ) then return mw.ustring.format( '%04i', input ) end
-- otherwise use regular expression match input = mw.ustring.match( input, '^(-?%d%d?%d?%d?)-' ) if input then return mw.ustring.format( '%04i', input ) else return end end
--[[ ISOdate
This function is the core part of the ISOdate template.
Usage: target_string
Parameters:
1: The date string lang: The language to display it in form: Language format (genitive, etc.) for some languages class: CSS class for the
]] function p.ISOdate(frame) local datestr, succeded datestr, succeded = p._ISOdate( mw.text.trim(frame.args[1]), frame.args["lang"], -- language frame.args["trim_year"] or '100-999' -- by default pad one and 2 digit years to be 4 digit long, while keeping 3 digit years as is ) return datestr end
function p._ISOdate(datestr, lang, trim_year)
-- pattern: regexp - regular expresion to test; dlen - number of date elements; tail = which element is a "tail" if any -- regexp hints: -- 1) Strings starting with "^" and ending with "$" indicate whole string match -- 2) optional tail part copied as-is and following the main parsed part of the date have to be separated from the date by a whitespace, so "(\s.+)?" local patterns = { -- strings starting with YYYY-MM-DD. Year 1-4 digits, the rest 1-2 {dlen=3, tail=4, regexp="^(%d%d?%d?%d?)-(%d%d?)-(%d%d?)(%s.+)"}, {dlen=3, tail=0, regexp="^(%d%d?%d?%d?)-(%d%d?)-(%d%d?)$"}, -- strings starting with YYYY-MM. Year 3-4 digits, month 2 digits -- (want to avoit converting to dates strings like 10-5 = 5 {dlen=2, tail=3, regexp="^(%d%d%d%d?)-(%d%d)(%s.+)"}, -- if whole string is in YYYY-MM form: If Year 1-4 digits, month 1-2 digits {dlen=2, tail=0, regexp="^(%d%d?%d?%d?)-(%d%d?)$"}, -- string starts with a number -> it has to be 3 or 4 digit long to be a year {dlen=1, tail=2, regexp="^(%d%d%d%d?)(%s.+)"}, -- if whole string is a number (1-4 digit long) than it will be interpreted as a year {dlen=1, tail=0, regexp="^(%d%d?%d?%d?)$"}, }
-- create datevec based on which variables are provided local datevec, tail, formatNum datevec, tail, formatNum = p.test_date_formats(datestr, patterns) if datevec[1]== or datevec[1]==nil then -- quickly return if datestr does not look like date (it could be a template) return datestr, false end
-- call p._Date function to format date string local succeded, datestr2 succeded, datestr2 = pcall( D._Date, datevec, lang, trim_year) if succeded and datestr2~= then return mw.text.trim( datestr2 .. tail), true else -- in case of errors return the original string return datestr, false end end
function p.ISOdate_extended(frame) -- pattern: regexp - regular expresion to test; dlen - number of date elements; tail = which element is a "tail" if any -- regexp hints: -- 1) Strings starting with "^" and ending with "$" indicate whole string match -- 2) optional tail part copied as-is and following the main parsed part of the date have to be separated from the date by a whitespace, so "(\s.+)?"
local datestr, succeded datestr, succeded = p._ISOdate( mw.text.trim(frame.args[1]), frame.args["lang"], -- language frame.args["trim_year"] or '100-999' -- by default pad one and 2 digit years to be 4 digit long, while keeping 3 digit years as is ) if succeded then return datestr end
local datevec, tail, formatNum, category = datevec, tail, formatNum = p.test_date_formats(frame.args[1], patterns) if formatNum==1 or formatNum==2 then vec = datevec; if tonumber(datevec[1])>12 then frame.args[1] = string.format('%04i-%02i-%02i', datevec[3], datevec[2], datevec[1] ) category = return mw.text.trim( p.ISOdate(frame) .. tail); elseif tonumber(datevec[2])>12 then frame.args[1] = string.format('%04i-%02i-%02i', datevec[3], datevec[1], datevec[2] ) category = return mw.text.trim( p.ISOdate(frame) .. tail); end elseif (formatNum==3 or formatNum==4) and (datevec[3]== or datevec[3]~=nil) then local str = mw.getCurrentFrame():callParserFunction( "#time", { 'Y-m-d', datestr} ) local vec = {str:match( "^(%d%d?%d?%d?)-(%d%d?)-(%d%d?)$" )} if vec and vec[1]~=nil then frame.args[1] = string.format('%04i-%02i-%02i', vec[1], vec[2], vec[3] ) category = return p.ISOdate(frame); end end return datestr end
function p.test_date_formats(datestr, patterns) -- pattern: regexp - regular expresion to test; dlen - number of date elements; tail = which element is a "tail" if any
local datevec = {,,,,,} local tail = local vec, pat local formatNum = 0 for i, pat in ipairs( patterns ) do vec = {datestr:match( pat.regexp )} if vec and vec[1]~=nil then for j=1,pat.dlen do datevec[j] = vec[j] end if pat.tail>0 and vec[pat.tail]~=nil then tail = mw.ustring.gsub(' ' .. vec[pat.tail], ' +', ' ') end formatNum = i break end end return datevec, tail, formatNum end
return p